Solve 1/sqrt{3-sqrt{2}}

$$\frac { 1 } { \sqrt { 3 } - \sqrt { 2 } }$$

Evaluate

$$\sqrt{2}+\sqrt{3}\approx 3.14626437$$

Solution Steps

Rationalize the denominator of \frac{1}{\sqrt{3}-\sqrt{2}} by multiplying numerator and denominator by \sqrt{3}+\sqrt{2}.

$$\frac{\sqrt{3}+\sqrt{2}}{\left(\sqrt{3}-\sqrt{2}\right)\left(\sqrt{3}+\sqrt{2}\right)}$$

Consider \left(\sqrt{3}-\sqrt{2}\right)\left(\sqrt{3}+\sqrt{2}\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{\sqrt{3}+\sqrt{2}}{\left(\sqrt{3}\right)^{2}-\left(\sqrt{2}\right)^{2}}$$

Square \sqrt{3}. Square \sqrt{2}.

$$\frac{\sqrt{3}+\sqrt{2}}{3-2}$$

Subtract 2 from 3 to get 1.

$$\frac{\sqrt{3}+\sqrt{2}}{1}$$

Anything divided by one gives itself.

$$\sqrt{3}+\sqrt{2}$$