Solve 1/sqrt{(x)}=V(x)-2

$$\frac { 1 } { \sqrt { ( x ) } } = V ( x ) - 2$$

Solve for V

$$V=\frac{2}{x}+\frac{1}{x^{\frac{3}{2}}}$$

$$x>0$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$Vx-2=\frac{1}{\sqrt{x}}$$

Add 2 to both sides.

$$Vx=\frac{1}{\sqrt{x}}+2$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 2 times \frac{\sqrt{x}}{\sqrt{x}}.

$$Vx=\frac{1}{\sqrt{x}}+\frac{2\sqrt{x}}{\sqrt{x}}$$

Since \frac{1}{\sqrt{x}} and \frac{2\sqrt{x}}{\sqrt{x}} have the same denominator, add them by adding their numerators.

$$Vx=\frac{1+2\sqrt{x}}{\sqrt{x}}$$

The equation is in standard form.

$$xV=\frac{2\sqrt{x}+1}{\sqrt{x}}$$

Divide both sides by x.

$$\frac{xV}{x}=\frac{2+\frac{1}{\sqrt{x}}}{x}$$

Dividing by x undoes the multiplication by x.

$$V=\frac{2+\frac{1}{\sqrt{x}}}{x}$$

Divide \frac{1}{\sqrt{x}}+2 by x.

$$V=\frac{2}{x}+\frac{1}{x^{\frac{3}{2}}}$$