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\frac{\left(1\times 4+1\right)\times 3}{4\left(3\times 3+1\right)}=\frac{x}{\frac{2}{5}}
Divide \frac{1\times 4+1}{4} by \frac{3\times 3+1}{3} by multiplying \frac{1\times 4+1}{4} by the reciprocal of \frac{3\times 3+1}{3}.
\frac{\left(4+1\right)\times 3}{4\left(3\times 3+1\right)}=\frac{x}{\frac{2}{5}}
Multiply 1 and 4 to get 4.
\frac{5\times 3}{4\left(3\times 3+1\right)}=\frac{x}{\frac{2}{5}}
Add 4 and 1 to get 5.
\frac{15}{4\left(3\times 3+1\right)}=\frac{x}{\frac{2}{5}}
Multiply 5 and 3 to get 15.
\frac{15}{4\left(9+1\right)}=\frac{x}{\frac{2}{5}}
Multiply 3 and 3 to get 9.
\frac{15}{4\times 10}=\frac{x}{\frac{2}{5}}
Add 9 and 1 to get 10.
\frac{15}{40}=\frac{x}{\frac{2}{5}}
Multiply 4 and 10 to get 40.
\frac{3}{8}=\frac{x}{\frac{2}{5}}
Reduce the fraction \frac{15}{40} to lowest terms by extracting and canceling out 5.
\frac{x}{\frac{2}{5}}=\frac{3}{8}
Swap sides so that all variable terms are on the left hand side.
x=\frac{3}{8}\times \frac{2}{5}
Multiply both sides by \frac{2}{5}.
x=\frac{3\times 2}{8\times 5}
Multiply \frac{3}{8} times \frac{2}{5} by multiplying numerator times numerator and denominator times denominator.
x=\frac{6}{40}
Do the multiplications in the fraction \frac{3\times 2}{8\times 5}.
x=\frac{3}{20}
Reduce the fraction \frac{6}{40} to lowest terms by extracting and canceling out 2.