Solve 1^8*2^-2*8/2^2*2^-2=

$$\frac { 1 ^ { 8 } \cdot 2 ^ { - 2 } \cdot 8 } { 2 ^ { 2 } \cdot 2 ^ { - 2 } } =$$

Evaluate

$$2$$

Solution Steps

Multiply 2^{2} and 2^{-2} to get 1.

$$\frac{1^{8}\times 2^{-2}\times 8}{1}$$

Calculate 1 to the power of 8 and get 1.

$$\frac{1\times 2^{-2}\times 8}{1}$$

Calculate 2 to the power of -2 and get \frac{1}{4}.

$$\frac{1\times \frac{1}{4}\times 8}{1}$$

Multiply 1 and \frac{1}{4} to get \frac{1}{4}.

$$\frac{\frac{1}{4}\times 8}{1}$$

Multiply \frac{1}{4} and 8 to get 2.

$$\frac{2}{1}$$

Anything divided by one gives itself.

$$2$$

Factor

$$2$$