Solve 1^5+5^2/25^0-5^1=?

$$\frac { 1 ^ { 5 } + 5 ^ { 2 } } { 25 ^ { 0 } - 5 ^ { 1 } } = ?$$

Evaluate

$$-\frac{13}{2}=-6.5$$

Solution Steps

Calculate 1 to the power of 5 and get 1.

$$\frac{1+5^{2}}{25^{0}-5^{1}}$$

Calculate 5 to the power of 2 and get 25.

$$\frac{1+25}{25^{0}-5^{1}}$$

Add 1 and 25 to get 26.

$$\frac{26}{25^{0}-5^{1}}$$

Calculate 25 to the power of 0 and get 1.

$$\frac{26}{1-5^{1}}$$

Calculate 5 to the power of 1 and get 5.

$$\frac{26}{1-5}$$

Subtract 5 from 1 to get -4.

$$\frac{26}{-4}$$

Reduce the fraction \frac{26}{-4} to lowest terms by extracting and canceling out 2.

$$-\frac{13}{2}$$

Factor

$$-\frac{13}{2} = -6\frac{1}{2} = -6.5$$