Solve for b
b=-\frac{y}{8y-1}
y\neq 0\text{ and }y\neq \frac{1}{8}
Solve for y
y=\frac{b}{8b+1}
b\neq 0\text{ and }b\neq -\frac{1}{8}
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y\left(1+4b\right)=b\left(1-4y\right)
Variable b cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by by, the least common multiple of b,y.
y+4yb=b\left(1-4y\right)
Use the distributive property to multiply y by 1+4b.
y+4yb=b-4by
Use the distributive property to multiply b by 1-4y.
y+4yb-b=-4by
Subtract b from both sides.
y+4yb-b+4by=0
Add 4by to both sides.
y+8yb-b=0
Combine 4yb and 4by to get 8yb.
8yb-b=-y
Subtract y from both sides. Anything subtracted from zero gives its negation.
\left(8y-1\right)b=-y
Combine all terms containing b.
\frac{\left(8y-1\right)b}{8y-1}=-\frac{y}{8y-1}
Divide both sides by 8y-1.
b=-\frac{y}{8y-1}
Dividing by 8y-1 undoes the multiplication by 8y-1.
b=-\frac{y}{8y-1}\text{, }b\neq 0
Variable b cannot be equal to 0.
y\left(1+4b\right)=b\left(1-4y\right)
Variable y cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by by, the least common multiple of b,y.
y+4yb=b\left(1-4y\right)
Use the distributive property to multiply y by 1+4b.
y+4yb=b-4by
Use the distributive property to multiply b by 1-4y.
y+4yb+4by=b
Add 4by to both sides.
y+8yb=b
Combine 4yb and 4by to get 8yb.
\left(1+8b\right)y=b
Combine all terms containing y.
\left(8b+1\right)y=b
The equation is in standard form.
\frac{\left(8b+1\right)y}{8b+1}=\frac{b}{8b+1}
Divide both sides by 1+8b.
y=\frac{b}{8b+1}
Dividing by 1+8b undoes the multiplication by 1+8b.
y=\frac{b}{8b+1}\text{, }y\neq 0
Variable y cannot be equal to 0.
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