Solve 1+0.8x/4-0.88=2/3

$$\frac { 1 + 0.8 x } { 4 - 0.88 } = \frac { 2 } { 3 }$$

Solve for x

$$x=1.35$$

Steps for Solving Linear Equation

Subtract 0.88 from 4 to get 3.12.

$$\frac{1+0.8x}{3.12}=\frac{2}{3}$$

Divide each term of 1+0.8x by 3.12 to get \frac{1}{3.12}+\frac{0.8x}{3.12}.

$$\frac{1}{3.12}+\frac{0.8x}{3.12}=\frac{2}{3}$$

Expand \frac{1}{3.12} by multiplying both numerator and the denominator by 100.

$$\frac{100}{312}+\frac{0.8x}{3.12}=\frac{2}{3}$$

Reduce the fraction \frac{100}{312} to lowest terms by extracting and canceling out 4.

$$\frac{25}{78}+\frac{0.8x}{3.12}=\frac{2}{3}$$

Divide 0.8x by 3.12 to get \frac{10}{39}x.

$$\frac{25}{78}+\frac{10}{39}x=\frac{2}{3}$$

Subtract \frac{25}{78} from both sides.

$$\frac{10}{39}x=\frac{2}{3}-\frac{25}{78}$$

Least common multiple of 3 and 78 is 78. Convert \frac{2}{3} and \frac{25}{78} to fractions with denominator 78.

$$\frac{10}{39}x=\frac{52}{78}-\frac{25}{78}$$

Since \frac{52}{78} and \frac{25}{78} have the same denominator, subtract them by subtracting their numerators.

$$\frac{10}{39}x=\frac{52-25}{78}$$

Subtract 25 from 52 to get 27.

$$\frac{10}{39}x=\frac{27}{78}$$

Reduce the fraction \frac{27}{78} to lowest terms by extracting and canceling out 3.

$$\frac{10}{39}x=\frac{9}{26}$$

Divide both sides by \frac{10}{39}.

$$x=\frac{\frac{9}{26}}{\frac{10}{39}}$$

Express \frac{\frac{9}{26}}{\frac{10}{39}} as a single fraction.

$$x=\frac{9}{26\times \frac{10}{39}}$$

Multiply 26 and \frac{10}{39} to get \frac{20}{3}.

$$x=\frac{9}{\frac{20}{3}}$$