Solve 1+9/3/1+frac{3{4}}

$$\frac { 1 + \frac { 9 } { 3 } } { 1 + \frac { 3 } { 4 } }$$

Evaluate

$$\frac{16}{7}\approx 2.285714286$$

Solution Steps

Divide 9 by 3 to get 3.

$$\frac{1+3}{1+\frac{3}{4}}$$

Add 1 and 3 to get 4.

$$\frac{4}{1+\frac{3}{4}}$$

Convert 1 to fraction \frac{4}{4}.

$$\frac{4}{\frac{4}{4}+\frac{3}{4}}$$

Since \frac{4}{4} and \frac{3}{4} have the same denominator, add them by adding their numerators.

$$\frac{4}{\frac{4+3}{4}}$$

Add 4 and 3 to get 7.

$$\frac{4}{\frac{7}{4}}$$

Divide 4 by \frac{7}{4} by multiplying 4 by the reciprocal of \frac{7}{4}.

$$4\times \frac{4}{7}$$

Express 4\times \frac{4}{7} as a single fraction.

$$\frac{4\times 4}{7}$$

Multiply 4 and 4 to get 16.

$$\frac{16}{7}$$

Factor

$$\frac{2 ^ {4}}{7} = 2\frac{2}{7} = 2.2857142857142856$$