Solve 1+2/7/4+frac{5{7}}

$$\frac { 1 + \frac { 2 } { 7 } } { 4 + \frac { 5 } { 7 } }$$

Evaluate

$$\frac{3}{11}\approx 0.272727273$$

Solution Steps

Convert 1 to fraction \frac{7}{7}.

$$\frac{\frac{7}{7}+\frac{2}{7}}{4+\frac{5}{7}}$$

Since \frac{7}{7} and \frac{2}{7} have the same denominator, add them by adding their numerators.

$$\frac{\frac{7+2}{7}}{4+\frac{5}{7}}$$

Add 7 and 2 to get 9.

$$\frac{\frac{9}{7}}{4+\frac{5}{7}}$$

Convert 4 to fraction \frac{28}{7}.

$$\frac{\frac{9}{7}}{\frac{28}{7}+\frac{5}{7}}$$

Since \frac{28}{7} and \frac{5}{7} have the same denominator, add them by adding their numerators.

$$\frac{\frac{9}{7}}{\frac{28+5}{7}}$$

Add 28 and 5 to get 33.

$$\frac{\frac{9}{7}}{\frac{33}{7}}$$

Divide \frac{9}{7} by \frac{33}{7} by multiplying \frac{9}{7} by the reciprocal of \frac{33}{7}.

$$\frac{9}{7}\times \frac{7}{33}$$

Multiply \frac{9}{7} times \frac{7}{33} by multiplying numerator times numerator and denominator times denominator.

$$\frac{9\times 7}{7\times 33}$$

Cancel out 7 in both numerator and denominator.

$$\frac{9}{33}$$

Reduce the fraction \frac{9}{33} to lowest terms by extracting and canceling out 3.

$$\frac{3}{11}$$

Factor

$$\frac{3}{11} = 0.2727272727272727$$