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\frac{1+\frac{15}{2}}{1-\frac{\sqrt{3}}{2}}
Divide 1 by 1 to get 1.
\frac{\frac{2}{2}+\frac{15}{2}}{1-\frac{\sqrt{3}}{2}}
Convert 1 to fraction \frac{2}{2}.
\frac{\frac{2+15}{2}}{1-\frac{\sqrt{3}}{2}}
Since \frac{2}{2} and \frac{15}{2} have the same denominator, add them by adding their numerators.
\frac{\frac{17}{2}}{1-\frac{\sqrt{3}}{2}}
Add 2 and 15 to get 17.
\frac{\frac{17}{2}}{\frac{2}{2}-\frac{\sqrt{3}}{2}}
To add or subtract expressions, expand them to make their denominators the same. Multiply 1 times \frac{2}{2}.
\frac{\frac{17}{2}}{\frac{2-\sqrt{3}}{2}}
Since \frac{2}{2} and \frac{\sqrt{3}}{2} have the same denominator, subtract them by subtracting their numerators.
\frac{17\times 2}{2\left(2-\sqrt{3}\right)}
Divide \frac{17}{2} by \frac{2-\sqrt{3}}{2} by multiplying \frac{17}{2} by the reciprocal of \frac{2-\sqrt{3}}{2}.
\frac{17}{-\sqrt{3}+2}
Cancel out 2 in both numerator and denominator.
\frac{17\left(-\sqrt{3}-2\right)}{\left(-\sqrt{3}+2\right)\left(-\sqrt{3}-2\right)}
Rationalize the denominator of \frac{17}{-\sqrt{3}+2} by multiplying numerator and denominator by -\sqrt{3}-2.
\frac{17\left(-\sqrt{3}-2\right)}{\left(-\sqrt{3}\right)^{2}-2^{2}}
Consider \left(-\sqrt{3}+2\right)\left(-\sqrt{3}-2\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{17\left(-\sqrt{3}-2\right)}{\left(-1\right)^{2}\left(\sqrt{3}\right)^{2}-2^{2}}
Expand \left(-\sqrt{3}\right)^{2}.
\frac{17\left(-\sqrt{3}-2\right)}{1\left(\sqrt{3}\right)^{2}-2^{2}}
Calculate -1 to the power of 2 and get 1.
\frac{17\left(-\sqrt{3}-2\right)}{1\times 3-2^{2}}
The square of \sqrt{3} is 3.
\frac{17\left(-\sqrt{3}-2\right)}{3-2^{2}}
Multiply 1 and 3 to get 3.
\frac{17\left(-\sqrt{3}-2\right)}{3-4}
Calculate 2 to the power of 2 and get 4.
\frac{17\left(-\sqrt{3}-2\right)}{-1}
Subtract 4 from 3 to get -1.
-17\left(-\sqrt{3}-2\right)
Anything divided by -1 gives its opposite.
17\sqrt{3}+34
Use the distributive property to multiply -17 by -\sqrt{3}-2.