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0\times 5x^{3}-6x+8=0
Variable x cannot be equal to any of the values 0,1 since division by zero is not defined. Multiply both sides of the equation by \left(x-1\right)x^{2}.
0x^{3}-6x+8=0
Multiply 0 and 5 to get 0.
0-6x+8=0
Anything times zero gives zero.
8-6x=0
Add 0 and 8 to get 8.
-6x=-8
Subtract 8 from both sides. Anything subtracted from zero gives its negation.
x=\frac{-8}{-6}
Divide both sides by -6.
x=\frac{4}{3}
Reduce the fraction \frac{-8}{-6} to lowest terms by extracting and canceling out -2.