Solve frac{00000ab^{9}cd^{5}e^{-5}}{5a^4b^2cd^9c^-3}=

$$\frac { 00000 a b ^ { 9 } c d ^ { 5 } e ^ { - 5 } } { 5 a ^ { 4 } b ^ { 2 } c d ^ { 9 } c ^ { - 3 } } =$$

Evaluate

$$0$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and -3 to get -2.

$$\frac{0\times 0\times 0\times 0\times 0ab^{9}cd^{5}e^{-5}}{5a^{4}b^{2}c^{-2}d^{9}}$$

Cancel out 5ab^{2}d^{5} in both numerator and denominator.

$$\frac{0}{c^{-2}a^{3}d^{4}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent.

$$\frac{0}{a^{3}d^{4}}$$

Zero divided by any non-zero term gives zero.

$$0$$

Factor

$$0$$