Solve 0.6*10^-3+0.0012/0.002*10^-3?

$$\frac { 0.6 \cdot 10 ^ { - 3 } + 0.0012 } { 0.002 \cdot 10 ^ { - 3 } } ?$$

Evaluate

$$900$$

Solution Steps

Calculate 10 to the power of -3 and get \frac{1}{1000}.

$$\frac{0.6\times \frac{1}{1000}+0.0012}{0.002\times 10^{-3}}$$

Multiply 0.6 and \frac{1}{1000} to get \frac{3}{5000}.

$$\frac{\frac{3}{5000}+0.0012}{0.002\times 10^{-3}}$$

Add \frac{3}{5000} and 0.0012 to get \frac{9}{5000}.

$$\frac{\frac{9}{5000}}{0.002\times 10^{-3}}$$

Calculate 10 to the power of -3 and get \frac{1}{1000}.

$$\frac{\frac{9}{5000}}{0.002\times \frac{1}{1000}}$$

Multiply 0.002 and \frac{1}{1000} to get \frac{1}{500000}.

$$\frac{\frac{9}{5000}}{\frac{1}{500000}}$$

Divide \frac{9}{5000} by \frac{1}{500000} by multiplying \frac{9}{5000} by the reciprocal of \frac{1}{500000}.

$$\frac{9}{5000}\times 500000$$

Multiply \frac{9}{5000} and 500000 to get 900.

$$900$$

Factor

$$2^{2}\times 3^{2}\times 5^{2}$$