Solve 0.4y+0.9/5-0.3+0.2y/0.3=1

$$\frac { 0.4 y + 0.9 } { 5 } - \frac { 0.3 + 0.2 y } { 0.3 } = 1$$

Solve for y

$$y = -\frac{273}{88} = -3\frac{9}{88} \approx -3.102272727$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 5.

$$0.4y+0.9-5\times \frac{0.3+0.2y}{0.3}=5$$

Divide each term of 0.3+0.2y by 0.3 to get \frac{0.3}{0.3}+\frac{0.2y}{0.3}.

$$0.4y+0.9-5\left(\frac{0.3}{0.3}+\frac{0.2y}{0.3}\right)=5$$

Divide 0.3 by 0.3 to get 1.

$$0.4y+0.9-5\left(1+\frac{0.2y}{0.3}\right)=5$$

Divide 0.2y by 0.3 to get \frac{2}{3}y.

$$0.4y+0.9-5\left(1+\frac{2}{3}y\right)=5$$

Use the distributive property to multiply -5 by 1+\frac{2}{3}y.

$$0.4y+0.9-5-\frac{10}{3}y=5$$

Subtract 5 from 0.9 to get -4.1.

$$0.4y-4.1-\frac{10}{3}y=5$$

Combine 0.4y and -\frac{10}{3}y to get -\frac{44}{15}y.

$$-\frac{44}{15}y-4.1=5$$

Add 4.1 to both sides.

$$-\frac{44}{15}y=5+4.1$$

Add 5 and 4.1 to get 9.1.

$$-\frac{44}{15}y=9.1$$

Divide both sides by -\frac{44}{15}.

$$y=\frac{9.1}{-\frac{44}{15}}$$