Solve 0.2/sin60^circ

$$\frac { 0.2 } { \sin 60 ^ { \circ } }$$

Evaluate

$$\frac{2\sqrt{3}}{15}\approx 0.230940108$$

Solution Steps

Get the value of \sin(60) from trigonometric values table.

$$\frac{0.2}{\frac{\sqrt{3}}{2}}$$

Divide 0.2 by \frac{\sqrt{3}}{2} by multiplying 0.2 by the reciprocal of \frac{\sqrt{3}}{2}.

$$\frac{0.2\times 2}{\sqrt{3}}$$

Rationalize the denominator of \frac{0.2\times 2}{\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.

$$\frac{0.2\times 2\sqrt{3}}{\left(\sqrt{3}\right)^{2}}$$

The square of \sqrt{3} is 3.

$$\frac{0.2\times 2\sqrt{3}}{3}$$

Multiply 0.2 and 2 to get 0.4.

$$\frac{0.4\sqrt{3}}{3}$$

Divide 0.4\sqrt{3} by 3 to get \frac{2}{15}\sqrt{3}.

$$\frac{2}{15}\sqrt{3}$$