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\frac{0.1x}{1.2}+\frac{-0.4}{1.2}-1=\frac{0.2x+1}{0.3}
Divide each term of 0.1x-0.4 by 1.2 to get \frac{0.1x}{1.2}+\frac{-0.4}{1.2}.
\frac{1}{12}x+\frac{-0.4}{1.2}-1=\frac{0.2x+1}{0.3}
Divide 0.1x by 1.2 to get \frac{1}{12}x.
\frac{1}{12}x+\frac{-4}{12}-1=\frac{0.2x+1}{0.3}
Expand \frac{-0.4}{1.2} by multiplying both numerator and the denominator by 10.
\frac{1}{12}x-\frac{1}{3}-1=\frac{0.2x+1}{0.3}
Reduce the fraction \frac{-4}{12} to lowest terms by extracting and canceling out 4.
\frac{1}{12}x-\frac{1}{3}-\frac{3}{3}=\frac{0.2x+1}{0.3}
Convert 1 to fraction \frac{3}{3}.
\frac{1}{12}x+\frac{-1-3}{3}=\frac{0.2x+1}{0.3}
Since -\frac{1}{3} and \frac{3}{3} have the same denominator, subtract them by subtracting their numerators.
\frac{1}{12}x-\frac{4}{3}=\frac{0.2x+1}{0.3}
Subtract 3 from -1 to get -4.
\frac{1}{12}x-\frac{4}{3}=\frac{0.2x}{0.3}+\frac{1}{0.3}
Divide each term of 0.2x+1 by 0.3 to get \frac{0.2x}{0.3}+\frac{1}{0.3}.
\frac{1}{12}x-\frac{4}{3}=\frac{2}{3}x+\frac{1}{0.3}
Divide 0.2x by 0.3 to get \frac{2}{3}x.
\frac{1}{12}x-\frac{4}{3}=\frac{2}{3}x+\frac{10}{3}
Expand \frac{1}{0.3} by multiplying both numerator and the denominator by 10.
\frac{1}{12}x-\frac{4}{3}-\frac{2}{3}x=\frac{10}{3}
Subtract \frac{2}{3}x from both sides.
-\frac{7}{12}x-\frac{4}{3}=\frac{10}{3}
Combine \frac{1}{12}x and -\frac{2}{3}x to get -\frac{7}{12}x.
-\frac{7}{12}x=\frac{10}{3}+\frac{4}{3}
Add \frac{4}{3} to both sides.
-\frac{7}{12}x=\frac{10+4}{3}
Since \frac{10}{3} and \frac{4}{3} have the same denominator, add them by adding their numerators.
-\frac{7}{12}x=\frac{14}{3}
Add 10 and 4 to get 14.
x=\frac{\frac{14}{3}}{-\frac{7}{12}}
Divide both sides by -\frac{7}{12}.
x=\frac{14}{3\left(-\frac{7}{12}\right)}
Express \frac{\frac{14}{3}}{-\frac{7}{12}} as a single fraction.
x=\frac{14}{-1.75}
Multiply 3 and -\frac{7}{12} to get -1.75.
x=\frac{1400}{-175}
Expand \frac{14}{-1.75} by multiplying both numerator and the denominator by 100.
x=-8
Divide 1400 by -175 to get -8.