Solve for x
x=2
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\frac{0.05}{0.03}+\frac{0.02x}{0.03}-\frac{1-0.3x}{0.2}=1
Divide each term of 0.05+0.02x by 0.03 to get \frac{0.05}{0.03}+\frac{0.02x}{0.03}.
\frac{5}{3}+\frac{0.02x}{0.03}-\frac{1-0.3x}{0.2}=1
Expand \frac{0.05}{0.03} by multiplying both numerator and the denominator by 100.
\frac{5}{3}+\frac{2}{3}x-\frac{1-0.3x}{0.2}=1
Divide 0.02x by 0.03 to get \frac{2}{3}x.
\frac{5}{3}+\frac{2}{3}x-\left(\frac{1}{0.2}+\frac{-0.3x}{0.2}\right)=1
Divide each term of 1-0.3x by 0.2 to get \frac{1}{0.2}+\frac{-0.3x}{0.2}.
\frac{5}{3}+\frac{2}{3}x-\left(\frac{10}{2}+\frac{-0.3x}{0.2}\right)=1
Expand \frac{1}{0.2} by multiplying both numerator and the denominator by 10.
\frac{5}{3}+\frac{2}{3}x-\left(5+\frac{-0.3x}{0.2}\right)=1
Divide 10 by 2 to get 5.
\frac{5}{3}+\frac{2}{3}x-\left(5-1.5x\right)=1
Divide -0.3x by 0.2 to get -1.5x.
\frac{5}{3}+\frac{2}{3}x-5-\left(-1.5x\right)=1
To find the opposite of 5-1.5x, find the opposite of each term.
\frac{5}{3}+\frac{2}{3}x-5+1.5x=1
The opposite of -1.5x is 1.5x.
\frac{5}{3}+\frac{2}{3}x-\frac{15}{3}+1.5x=1
Convert 5 to fraction \frac{15}{3}.
\frac{5-15}{3}+\frac{2}{3}x+1.5x=1
Since \frac{5}{3} and \frac{15}{3} have the same denominator, subtract them by subtracting their numerators.
-\frac{10}{3}+\frac{2}{3}x+1.5x=1
Subtract 15 from 5 to get -10.
-\frac{10}{3}+\frac{13}{6}x=1
Combine \frac{2}{3}x and 1.5x to get \frac{13}{6}x.
\frac{13}{6}x=1+\frac{10}{3}
Add \frac{10}{3} to both sides.
\frac{13}{6}x=\frac{3}{3}+\frac{10}{3}
Convert 1 to fraction \frac{3}{3}.
\frac{13}{6}x=\frac{3+10}{3}
Since \frac{3}{3} and \frac{10}{3} have the same denominator, add them by adding their numerators.
\frac{13}{6}x=\frac{13}{3}
Add 3 and 10 to get 13.
x=\frac{\frac{13}{3}}{\frac{13}{6}}
Divide both sides by \frac{13}{6}.
x=\frac{13}{3\times \frac{13}{6}}
Express \frac{\frac{13}{3}}{\frac{13}{6}} as a single fraction.
x=\frac{13}{6.5}
Multiply 3 and \frac{13}{6} to get 6.5.
x=\frac{130}{65}
Expand \frac{13}{6.5} by multiplying both numerator and the denominator by 10.
x=2
Divide 130 by 65 to get 2.
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