Solve 0,4^2-(-1/3)^2/0,4-2frac{1{3}}

$$\frac { 0,4 ^ { 2 } - ( - \frac { 1 } { 3 } ) ^ { 2 } } { 0,4 - 2 \frac { 1 } { 3 } }$$

Evaluate

$$\frac{5}{87}\approx 0,057471264$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$\frac{0\times 16-\left(-\frac{1}{3}\right)^{2}}{0,4-\frac{2\times 3+1}{3}}$$

Multiply 0 and 16 to get 0.

$$\frac{0-\left(-\frac{1}{3}\right)^{2}}{0,4-\frac{2\times 3+1}{3}}$$

Calculate -\frac{1}{3} to the power of 2 and get \frac{1}{9}.

$$\frac{0-\frac{1}{9}}{0,4-\frac{2\times 3+1}{3}}$$

Subtract \frac{1}{9} from 0 to get -\frac{1}{9}.

$$\frac{-\frac{1}{9}}{0,4-\frac{2\times 3+1}{3}}$$

Multiply 2 and 3 to get 6.

$$\frac{-\frac{1}{9}}{0,4-\frac{6+1}{3}}$$

Add 6 and 1 to get 7.

$$\frac{-\frac{1}{9}}{0,4-\frac{7}{3}}$$

Convert decimal number 0,4 to fraction \frac{4}{10}. Reduce the fraction \frac{4}{10} to lowest terms by extracting and canceling out 2.

$$\frac{-\frac{1}{9}}{\frac{2}{5}-\frac{7}{3}}$$

Least common multiple of 5 and 3 is 15. Convert \frac{2}{5} and \frac{7}{3} to fractions with denominator 15.

$$\frac{-\frac{1}{9}}{\frac{6}{15}-\frac{35}{15}}$$

Since \frac{6}{15} and \frac{35}{15} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-\frac{1}{9}}{\frac{6-35}{15}}$$

Subtract 35 from 6 to get -29.

$$\frac{-\frac{1}{9}}{-\frac{29}{15}}$$

Divide -\frac{1}{9} by -\frac{29}{15} by multiplying -\frac{1}{9} by the reciprocal of -\frac{29}{15}.

$$-\frac{1}{9}\left(-\frac{15}{29}\right)$$

Multiply -\frac{1}{9} times -\frac{15}{29} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-\left(-15\right)}{9\times 29}$$

Do the multiplications in the fraction \frac{-\left(-15\right)}{9\times 29}.

$$\frac{15}{261}$$

Reduce the fraction \frac{15}{261} to lowest terms by extracting and canceling out 3.

$$\frac{5}{87}$$

Factor

$$\frac{5}{3 \cdot 29} = 0.05747126436781609$$