Solve frac{0,1^{-3}*5^{-2}}{(5/64*0,4^{3})^-2}*((1/5)^-2*0,25^2)^-3

$$\frac { 0,1 ^ { - 3 } \cdot 5 ^ { - 2 } } { ( \frac { 5 } { 64 } \cdot 0,4 ^ { 3 } ) ^ { - 2 } } \cdot ( ( \frac { 1 } { 5 } ) ^ { - 2 } \cdot 0,25 ^ { 2 } ) ^ { - 3 }$$

Evaluate

$$\text{Indeterminate}$$

Solution Steps

Calculate 1 to the power of -3 and get 1.

$$\frac{0\times 1\times 5^{-2}}{\left(\frac{5}{64}\times 0\times 4^{3}\right)^{-2}}\times \left(\left(\frac{1}{5}\right)^{-2}\times 0\times 25^{2}\right)^{-3}$$

Multiply 0 and 1 to get 0.

$$\frac{0\times 5^{-2}}{\left(\frac{5}{64}\times 0\times 4^{3}\right)^{-2}}\times \left(\left(\frac{1}{5}\right)^{-2}\times 0\times 25^{2}\right)^{-3}$$

Calculate 5 to the power of -2 and get \frac{1}{25}.

$$\frac{0\times \frac{1}{25}}{\left(\frac{5}{64}\times 0\times 4^{3}\right)^{-2}}\times \left(\left(\frac{1}{5}\right)^{-2}\times 0\times 25^{2}\right)^{-3}$$

Multiply 0 and \frac{1}{25} to get 0.

$$\frac{0}{\left(\frac{5}{64}\times 0\times 4^{3}\right)^{-2}}\times \left(\left(\frac{1}{5}\right)^{-2}\times 0\times 25^{2}\right)^{-3}$$

Multiply \frac{5}{64} and 0 to get 0.

$$\frac{0}{\left(0\times 4^{3}\right)^{-2}}\times \left(\left(\frac{1}{5}\right)^{-2}\times 0\times 25^{2}\right)^{-3}$$

Calculate 4 to the power of 3 and get 64.

$$\frac{0}{\left(0\times 64\right)^{-2}}\times \left(\left(\frac{1}{5}\right)^{-2}\times 0\times 25^{2}\right)^{-3}$$

Multiply 0 and 64 to get 0.

$$\frac{0}{0^{-2}}\times \left(\left(\frac{1}{5}\right)^{-2}\times 0\times 25^{2}\right)^{-3}$$

Calculate \frac{1}{5} to the power of -2 and get 25.

$$\frac{0}{0^{-2}}\times \left(25\times 0\times 25^{2}\right)^{-3}$$

Multiply 25 and 0 to get 0.

$$\frac{0}{0^{-2}}\times \left(0\times 25^{2}\right)^{-3}$$

Calculate 25 to the power of 2 and get 625.

$$\frac{0}{0^{-2}}\times \left(0\times 625\right)^{-3}$$

Multiply 0 and 625 to get 0.

$$\frac{0}{0^{-2}}\times 0^{-3}$$

Express \frac{0}{0^{-2}}\times 0^{-3} as a single fraction.

$$\frac{0\times 0^{-3}}{0^{-2}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent.

$$0^{-3}\times 0^{3}$$

Multiply 0^{-3} and 0^{3} to get 1.

$$1$$

Factor

$$\text{Indeterminate}$$