Solve 0-h/a-frac{b+c{2}}

$$\frac { 0 - h } { a - \frac { b + c } { 2 } }$$

Evaluate

$$-\frac{2h}{2a-b-c}$$

Short Solution Steps

Anything plus zero gives itself.

$$\frac{-h}{a-\frac{b+c}{2}}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply a times \frac{2}{2}.

$$\frac{-h}{\frac{2a}{2}-\frac{b+c}{2}}$$

Since \frac{2a}{2} and \frac{b+c}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-h}{\frac{2a-\left(b+c\right)}{2}}$$

Do the multiplications in 2a-\left(b+c\right).

$$\frac{-h}{\frac{2a-b-c}{2}}$$

Divide -h by \frac{2a-b-c}{2} by multiplying -h by the reciprocal of \frac{2a-b-c}{2}.

$$\frac{-h\times 2}{2a-b-c}$$

Multiply -1 and 2 to get -2.

$$\frac{-2h}{2a-b-c}$$

Expand

$$\frac{2h}{c+b-2a}$$

Short Solution Steps

Anything plus zero gives itself.

$$\frac{-h}{a-\frac{b+c}{2}}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply a times \frac{2}{2}.

$$\frac{-h}{\frac{2a}{2}-\frac{b+c}{2}}$$

Since \frac{2a}{2} and \frac{b+c}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-h}{\frac{2a-\left(b+c\right)}{2}}$$

Do the multiplications in 2a-\left(b+c\right).

$$\frac{-h}{\frac{2a-b-c}{2}}$$

Divide -h by \frac{2a-b-c}{2} by multiplying -h by the reciprocal of \frac{2a-b-c}{2}.

$$\frac{-h\times 2}{2a-b-c}$$

Multiply -1 and 2 to get -2.

$$\frac{-2h}{2a-b-c}$$