Solve 0/a[8-2/8{8-2/a(8-2/2-frac{2}{4})}]

$$\frac { 0 } { a } [ 8 - \frac { 2 } { 8 } \{ 8 - \frac { 2 } { a } ( 8 - \frac { 2 } { 2 } - \frac { 2 } { 4 } ) \} ]$$

Evaluate

$$0$$

Short Solution Steps

Divide 2 by 2 to get 1.

$$\frac{0}{a}\left(8-\frac{2}{8}\left(8-\frac{2}{a}\left(8-1-\frac{2}{4}\right)\right)\right)$$

Zero divided by any non-zero term gives zero.

$$0\left(8-\frac{2}{8}\left(8-\frac{2}{a}\left(8-1-\frac{2}{4}\right)\right)\right)$$

Reduce the fraction \frac{2}{8} to lowest terms by extracting and canceling out 2.

$$0\left(8-\frac{1}{4}\left(8-\frac{2}{a}\left(8-1-\frac{2}{4}\right)\right)\right)$$

Subtract 1 from 8 to get 7.

$$0\left(8-\frac{1}{4}\left(8-\frac{2}{a}\left(7-\frac{2}{4}\right)\right)\right)$$

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$0\left(8-\frac{1}{4}\left(8-\frac{2}{a}\left(7-\frac{1}{2}\right)\right)\right)$$

Convert 7 to fraction \frac{14}{2}.

$$0\left(8-\frac{1}{4}\left(8-\frac{2}{a}\left(\frac{14}{2}-\frac{1}{2}\right)\right)\right)$$

Since \frac{14}{2} and \frac{1}{2} have the same denominator, subtract them by subtracting their numerators.

$$0\left(8-\frac{1}{4}\left(8-\frac{2}{a}\times \frac{14-1}{2}\right)\right)$$

Subtract 1 from 14 to get 13.

$$0\left(8-\frac{1}{4}\left(8-\frac{2}{a}\times \frac{13}{2}\right)\right)$$

Multiply \frac{2}{a} times \frac{13}{2} by multiplying numerator times numerator and denominator times denominator.

$$0\left(8-\frac{1}{4}\left(8-\frac{2\times 13}{a\times 2}\right)\right)$$

Cancel out 2 in both numerator and denominator.

$$0\left(8-\frac{1}{4}\left(8-\frac{13}{a}\right)\right)$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 8 times \frac{a}{a}.

$$0\left(8-\frac{1}{4}\left(\frac{8a}{a}-\frac{13}{a}\right)\right)$$

Since \frac{8a}{a} and \frac{13}{a} have the same denominator, subtract them by subtracting their numerators.

$$0\left(8-\frac{1}{4}\times \frac{8a-13}{a}\right)$$

Multiply \frac{1}{4} times \frac{8a-13}{a} by multiplying numerator times numerator and denominator times denominator.

$$0\left(8-\frac{8a-13}{4a}\right)$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 8 times \frac{4a}{4a}.

$$0\left(\frac{8\times 4a}{4a}-\frac{8a-13}{4a}\right)$$

Since \frac{8\times 4a}{4a} and \frac{8a-13}{4a} have the same denominator, subtract them by subtracting their numerators.

$$0\times \frac{8\times 4a-\left(8a-13\right)}{4a}$$

Do the multiplications in 8\times 4a-\left(8a-13\right).

$$0\times \frac{32a-8a+13}{4a}$$

Combine like terms in 32a-8a+13.

$$0\times \frac{24a+13}{4a}$$

Anything times zero gives zero.

$$0$$

Factor

$$0$$