Solve 0/3*5+1/5+2/5+3/5+frac{4}{5}+frac{5}{5}=frac{-10}{5}

$$\frac { 0 } { 3 \cdot 5 } + \frac { 1 } { 5 } + \frac { 2 } { 5 } + \frac { 3 } { 5 } + \frac { 4 } { 5 } + \frac { 5 } { 5 } = \frac { - 10 } { 5 }$$

Verify

Solution Steps

Divide 5 by 5 to get 1.

$$\frac{0}{3\times 5}+\frac{1}{5}+\frac{2}{5}+\frac{3}{5}+\frac{4}{5}+1=\frac{-10}{5}$$

Multiply 3 and 5 to get 15.

$$\frac{0}{15}+\frac{1}{5}+\frac{2}{5}+\frac{3}{5}+\frac{4}{5}+1=\frac{-10}{5}$$

Zero divided by any non-zero number gives zero.

$$0+\frac{1}{5}+\frac{2}{5}+\frac{3}{5}+\frac{4}{5}+1=\frac{-10}{5}$$

Add 0 and \frac{1}{5} to get \frac{1}{5}.

$$\frac{1}{5}+\frac{2}{5}+\frac{3}{5}+\frac{4}{5}+1=\frac{-10}{5}$$

Since \frac{1}{5} and \frac{2}{5} have the same denominator, add them by adding their numerators.

$$\frac{1+2}{5}+\frac{3}{5}+\frac{4}{5}+1=\frac{-10}{5}$$

Add 1 and 2 to get 3.

$$\frac{3}{5}+\frac{3}{5}+\frac{4}{5}+1=\frac{-10}{5}$$

Since \frac{3}{5} and \frac{3}{5} have the same denominator, add them by adding their numerators.

$$\frac{3+3}{5}+\frac{4}{5}+1=\frac{-10}{5}$$

Add 3 and 3 to get 6.

$$\frac{6}{5}+\frac{4}{5}+1=\frac{-10}{5}$$

Since \frac{6}{5} and \frac{4}{5} have the same denominator, add them by adding their numerators.

$$\frac{6+4}{5}+1=\frac{-10}{5}$$

Add 6 and 4 to get 10.

$$\frac{10}{5}+1=\frac{-10}{5}$$

Divide 10 by 5 to get 2.

$$2+1=\frac{-10}{5}$$

Add 2 and 1 to get 3.

$$3=\frac{-10}{5}$$

Divide -10 by 5 to get -2.

$$3=-2$$

Compare 3 and -2.

$$\text{false}$$