Solve 0^2-6x+8/1^2-6x+8=8

$$\frac { 0 ^ { 2 } - 6 x + 8 } { 1 ^ { 2 } - 6 x + 8 } = 8$$

Solve for x

$$x = \frac{32}{21} = 1\frac{11}{21} \approx 1.523809524$$

Steps for Solving Linear Equation

Variable x cannot be equal to \frac{3}{2} since division by zero is not defined. Multiply both sides of the equation by 3\left(-2x+3\right).

$$0^{2}-6x+8=24\left(-2x+3\right)$$

Calculate 0 to the power of 2 and get 0.

$$0-6x+8=24\left(-2x+3\right)$$

Add 0 and 8 to get 8.

$$8-6x=24\left(-2x+3\right)$$

Use the distributive property to multiply 24 by -2x+3.

$$8-6x=-48x+72$$

Add 48x to both sides.

$$8-6x+48x=72$$

Combine -6x and 48x to get 42x.

$$8+42x=72$$

Subtract 8 from both sides.

$$42x=72-8$$

Subtract 8 from 72 to get 64.

$$42x=64$$

Divide both sides by 42.

$$x=\frac{64}{42}$$

Reduce the fraction \frac{64}{42} to lowest terms by extracting and canceling out 2.

$$x=\frac{32}{21}$$