Solve 0+(-2/3)/2,1/8+0/2

$$\frac { 0 + ( - \frac { 2 } { 3 } ) } { 2 } , \frac { \frac { 1 } { 8 } + 0 } { 2 }$$

Sort

$$-\frac{1}{3},\frac{1}{16}$$

Solution Steps

Subtract \frac{2}{3} from 0 to get -\frac{2}{3}.

$$sort(\frac{-\frac{2}{3}}{2},\frac{\frac{1}{8}+0}{2})$$

Express \frac{-\frac{2}{3}}{2} as a single fraction.

$$sort(\frac{-2}{3\times 2},\frac{\frac{1}{8}+0}{2})$$

Multiply 3 and 2 to get 6.

$$sort(\frac{-2}{6},\frac{\frac{1}{8}+0}{2})$$

Reduce the fraction \frac{-2}{6} to lowest terms by extracting and canceling out 2.

$$sort(-\frac{1}{3},\frac{\frac{1}{8}+0}{2})$$

Add \frac{1}{8} and 0 to get \frac{1}{8}.

$$sort(-\frac{1}{3},\frac{\frac{1}{8}}{2})$$

Express \frac{\frac{1}{8}}{2} as a single fraction.

$$sort(-\frac{1}{3},\frac{1}{8\times 2})$$

Multiply 8 and 2 to get 16.

$$sort(-\frac{1}{3},\frac{1}{16})$$

Least common denominator of the numbers in the list -\frac{1}{3},\frac{1}{16} is 48. Convert numbers in the list to fractions with denominator 48.

$$-\frac{16}{48},\frac{3}{48}$$

Evaluate

$$-\frac{1}{3},\frac{1}{16}$$