Solve -x^2+1/(x^2+1)^2=0

$$\frac { - x ^ { 2 } + 1 } { ( x ^ { 2 } + 1 ) ^ { 2 } } = 0$$

Solve for x

$$x=1$$

$$x=-1$$

Steps by Finding Square Root

Multiply both sides of the equation by \left(x^{2}+1\right)^{2}.

$$-x^{2}+1=0$$

Subtract 1 from both sides. Anything subtracted from zero gives its negation.

$$-x^{2}=-1$$

Divide both sides by -1.

$$x^{2}=\frac{-1}{-1}$$

Divide -1 by -1 to get 1.

$$x^{2}=1$$

Take the square root of both sides of the equation.

$$x=1 x=-1$$

Steps Using the Quadratic Formula

Multiply both sides of the equation by \left(x^{2}+1\right)^{2}.

$$-x^{2}+1=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute -1 for a, 0 for b, and 1 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-1\right)}}{2\left(-1\right)}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-1\right)}}{2\left(-1\right)}$$

Multiply -4 times -1.

$$x=\frac{0±\sqrt{4}}{2\left(-1\right)}$$

Take the square root of 4.

$$x=\frac{0±2}{2\left(-1\right)}$$

Multiply 2 times -1.

$$x=\frac{0±2}{-2}$$

Now solve the equation x=\frac{0±2}{-2} when ± is plus. Divide 2 by -2.

$$x=-1$$

Now solve the equation x=\frac{0±2}{-2} when ± is minus. Divide -2 by -2.

$$x=1$$

The equation is now solved.

$$x=-1 x=1$$