Solve -9*2-(3-6)/1-(-2+1)-(-3)

$$\frac { - 9 \cdot 2 - ( 3 - 6 ) } { 1 - ( - 2 + 1 ) - ( - 3 ) }$$

Evaluate

$$-3$$

Solution Steps

Multiply -9 and 2 to get -18.

$$\frac{-18-\left(3-6\right)}{1-\left(-2+1\right)-\left(-3\right)}$$

Subtract 6 from 3 to get -3.

$$\frac{-18-\left(-3\right)}{1-\left(-2+1\right)-\left(-3\right)}$$

The opposite of -3 is 3.

$$\frac{-18+3}{1-\left(-2+1\right)-\left(-3\right)}$$

Add -18 and 3 to get -15.

$$\frac{-15}{1-\left(-2+1\right)-\left(-3\right)}$$

Add -2 and 1 to get -1.

$$\frac{-15}{1-\left(-1\right)-\left(-3\right)}$$

The opposite of -1 is 1.

$$\frac{-15}{1+1-\left(-3\right)}$$

Add 1 and 1 to get 2.

$$\frac{-15}{2-\left(-3\right)}$$

The opposite of -3 is 3.

$$\frac{-15}{2+3}$$

Add 2 and 3 to get 5.

$$\frac{-15}{5}$$

Divide -15 by 5 to get -3.

$$-3$$

Factor

$$-3$$