Solve -9*2-(3-6)/|4^2-2^5|-6

$$\frac { - 9 \cdot 2 - ( 3 - 6 ) } { | 4 ^ { 2 } - 2 ^ { 5 } | - 6 }$$

Evaluate

$$-\frac{3}{2}=-1.5$$

Solution Steps

Multiply -9 and 2 to get -18.

$$\frac{-18-\left(3-6\right)}{|4^{2}-2^{5}|-6}$$

Subtract 6 from 3 to get -3.

$$\frac{-18-\left(-3\right)}{|4^{2}-2^{5}|-6}$$

The opposite of -3 is 3.

$$\frac{-18+3}{|4^{2}-2^{5}|-6}$$

Add -18 and 3 to get -15.

$$\frac{-15}{|4^{2}-2^{5}|-6}$$

Calculate 4 to the power of 2 and get 16.

$$\frac{-15}{|16-2^{5}|-6}$$

Calculate 2 to the power of 5 and get 32.

$$\frac{-15}{|16-32|-6}$$

Subtract 32 from 16 to get -16.

$$\frac{-15}{|-16|-6}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -16 is 16.

$$\frac{-15}{16-6}$$

Subtract 6 from 16 to get 10.

$$\frac{-15}{10}$$

Reduce the fraction \frac{-15}{10} to lowest terms by extracting and canceling out 5.

$$-\frac{3}{2}$$

Factor

$$-\frac{3}{2} = -1\frac{1}{2} = -1.5$$