Solve -8^3+(-8)/40-2(-8)

$$\frac { - 8 ^ { 3 } + ( - 8 ) } { 40 - 2 ( - 8 ) }$$

Evaluate

$$-\frac{65}{7}\approx -9.285714286$$

Solution Steps

Calculate 8 to the power of 3 and get 512.

$$\frac{-512-8}{40-2\left(-8\right)}$$

Subtract 8 from -512 to get -520.

$$\frac{-520}{40-2\left(-8\right)}$$

Multiply 2 and -8 to get -16.

$$\frac{-520}{40-\left(-16\right)}$$

The opposite of -16 is 16.

$$\frac{-520}{40+16}$$

Add 40 and 16 to get 56.

$$\frac{-520}{56}$$

Reduce the fraction \frac{-520}{56} to lowest terms by extracting and canceling out 8.

$$-\frac{65}{7}$$

Factor

$$-\frac{65}{7} = -9\frac{2}{7} = -9.285714285714286$$