Solve -6,2+(-1,8)+33/5/41-15=

$$\frac { - 6,2 + ( - 1,8 ) + 3 \frac { 3 } { 5 } } { 41 - 15 } =$$

Evaluate

$$-\frac{11}{65}\approx -0,169230769$$

Solution Steps

Subtract 1,8 from -6,2 to get -8.

$$\frac{-8+\frac{3\times 5+3}{5}}{41-15}$$

Multiply 3 and 5 to get 15.

$$\frac{-8+\frac{15+3}{5}}{41-15}$$

Add 15 and 3 to get 18.

$$\frac{-8+\frac{18}{5}}{41-15}$$

Convert -8 to fraction -\frac{40}{5}.

$$\frac{-\frac{40}{5}+\frac{18}{5}}{41-15}$$

Since -\frac{40}{5} and \frac{18}{5} have the same denominator, add them by adding their numerators.

$$\frac{\frac{-40+18}{5}}{41-15}$$

Add -40 and 18 to get -22.

$$\frac{-\frac{22}{5}}{41-15}$$

Subtract 15 from 41 to get 26.

$$\frac{-\frac{22}{5}}{26}$$

Express \frac{-\frac{22}{5}}{26} as a single fraction.

$$\frac{-22}{5\times 26}$$

Multiply 5 and 26 to get 130.

$$\frac{-22}{130}$$

Reduce the fraction \frac{-22}{130} to lowest terms by extracting and canceling out 2.

$$-\frac{11}{65}$$

Factor

$$-\frac{11}{65} = -0.16923076923076924$$