Solve -6-3/-5-(-1)=y-2/0-4

$$\frac { - 6 - 3 } { - 5 - ( - 1 ) } = \frac { y - 2 } { 0 - 4 }$$

Solve for y

$$y=-7$$

Steps for Solving Linear Equation

Subtract 3 from -6 to get -9.

$$\frac{-9}{-5-\left(-1\right)}=\frac{y-2}{0-4}$$

The opposite of -1 is 1.

$$\frac{-9}{-5+1}=\frac{y-2}{0-4}$$

Add -5 and 1 to get -4.

$$\frac{-9}{-4}=\frac{y-2}{0-4}$$

Fraction \frac{-9}{-4} can be simplified to \frac{9}{4} by removing the negative sign from both the numerator and the denominator.

$$\frac{9}{4}=\frac{y-2}{0-4}$$

Subtract 4 from 0 to get -4.

$$\frac{9}{4}=\frac{y-2}{-4}$$

Multiply both numerator and denominator by -1.

$$\frac{9}{4}=\frac{-y+2}{4}$$

Divide each term of -y+2 by 4 to get -\frac{1}{4}y+\frac{1}{2}.

$$\frac{9}{4}=-\frac{1}{4}y+\frac{1}{2}$$

Swap sides so that all variable terms are on the left hand side.

$$-\frac{1}{4}y+\frac{1}{2}=\frac{9}{4}$$

Subtract \frac{1}{2} from both sides.

$$-\frac{1}{4}y=\frac{9}{4}-\frac{1}{2}$$

Least common multiple of 4 and 2 is 4. Convert \frac{9}{4} and \frac{1}{2} to fractions with denominator 4.

$$-\frac{1}{4}y=\frac{9}{4}-\frac{2}{4}$$

Since \frac{9}{4} and \frac{2}{4} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{1}{4}y=\frac{9-2}{4}$$

Subtract 2 from 9 to get 7.

$$-\frac{1}{4}y=\frac{7}{4}$$

Multiply both sides by -4, the reciprocal of -\frac{1}{4}.

$$y=\frac{7}{4}\left(-4\right)$$

Express \frac{7}{4}\left(-4\right) as a single fraction.

$$y=\frac{7\left(-4\right)}{4}$$

Multiply 7 and -4 to get -28.

$$y=\frac{-28}{4}$$

Divide -28 by 4 to get -7.

$$y=-7$$