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\frac{-6\sqrt{17}}{2\left(\sqrt{17}\right)^{2}}
Rationalize the denominator of \frac{-6}{2\sqrt{17}} by multiplying numerator and denominator by \sqrt{17}.
\frac{-6\sqrt{17}}{2\times 17}
The square of \sqrt{17} is 17.
\frac{-3\sqrt{17}}{17}
Cancel out 2 in both numerator and denominator.