Solve -5^2+(-5)^2/14^2-2^5/-2*3

$$\frac { - 5 ^ { 2 } + ( - 5 ) ^ { 2 } } { 14 ^ { 2 } - 2 ^ { 5 } / - 2 \cdot 3 }$$

Evaluate

$$0$$

Solution Steps

Calculate 5 to the power of 2 and get 25.

$$\frac{-25+\left(-5\right)^{2}}{14^{2}-\frac{2^{5}}{-2}\times 3}$$

Calculate -5 to the power of 2 and get 25.

$$\frac{-25+25}{14^{2}-\frac{2^{5}}{-2}\times 3}$$

Add -25 and 25 to get 0.

$$\frac{0}{14^{2}-\frac{2^{5}}{-2}\times 3}$$

Calculate 14 to the power of 2 and get 196.

$$\frac{0}{196-\frac{2^{5}}{-2}\times 3}$$

Calculate 2 to the power of 5 and get 32.

$$\frac{0}{196-\frac{32}{-2}\times 3}$$

Divide 32 by -2 to get -16.

$$\frac{0}{196-\left(-16\times 3\right)}$$

Multiply -16 and 3 to get -48.

$$\frac{0}{196-\left(-48\right)}$$

The opposite of -48 is 48.

$$\frac{0}{196+48}$$

Add 196 and 48 to get 244.

$$\frac{0}{244}$$

Zero divided by any non-zero number gives zero.

$$0$$

Factor

$$0$$