Solve -4/9-7/2-(sqrt{3})

$$\frac { - 4 } { 9 } - \frac { 7 } { 2 } - ( \sqrt { 3 } )$$

Evaluate

$$-\sqrt{3}-\frac{71}{18}\approx -5.676495252$$

Solution Steps

Fraction \frac{-4}{9} can be rewritten as -\frac{4}{9} by extracting the negative sign.

$$-\frac{4}{9}-\frac{7}{2}-\sqrt{3}$$

Least common multiple of 9 and 2 is 18. Convert -\frac{4}{9} and \frac{7}{2} to fractions with denominator 18.

$$-\frac{8}{18}-\frac{63}{18}-\sqrt{3}$$

Since -\frac{8}{18} and \frac{63}{18} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-8-63}{18}-\sqrt{3}$$

Subtract 63 from -8 to get -71.

$$-\frac{71}{18}-\sqrt{3}$$

Factor

$$\frac{-18 \sqrt{3} - 71}{18} = -5.676495252013321$$