Solve -4*(-3)x+3a*3(-3)-3/x^2-(-3)^2=0

$$\frac { - 4 \cdot ( - 3 ) x + 3 a \cdot 3 ( - 3 ) - 3 } { x ^ { 2 } - ( - 3 ) ^ { 2 } } = 0$$

Solve for a (complex solution)

$$a=\frac{4x-1}{9}$$

$$x\neq -3\text{ and }x\neq 3$$

Steps for Solving Linear Equation

Multiply both sides of the equation by \left(x-3\right)\left(x+3\right).

$$-4\left(-3\right)x+3a\times 3\left(-3\right)-3=0$$

Multiply -4 and -3 to get 12.

$$12x+3a\times 3\left(-3\right)-3=0$$

Multiply 3 and 3 to get 9.

$$12x+9a\left(-3\right)-3=0$$

Multiply 9 and -3 to get -27.

$$12x-27a-3=0$$

Subtract 12x from both sides. Anything subtracted from zero gives its negation.

$$-27a-3=-12x$$

Add 3 to both sides.

$$-27a=-12x+3$$

The equation is in standard form.

$$-27a=3-12x$$

Divide both sides by -27.

$$\frac{-27a}{-27}=\frac{3-12x}{-27}$$

Dividing by -27 undoes the multiplication by -27.

$$a=\frac{3-12x}{-27}$$

Divide -12x+3 by -27.

$$a=\frac{4x-1}{9}$$

Solve for x (complex solution)

$$x=\frac{9a+1}{4}$$

$$a\neq -\frac{13}{9}\text{ and }a\neq \frac{11}{9}$$

Steps for Solving Linear Equation

Variable x cannot be equal to any of the values -3,3 since division by zero is not defined. Multiply both sides of the equation by \left(x-3\right)\left(x+3\right).

$$-4\left(-3\right)x+3a\times 3\left(-3\right)-3=0$$

Multiply -4 and -3 to get 12.

$$12x+3a\times 3\left(-3\right)-3=0$$

Multiply 3 and 3 to get 9.

$$12x+9a\left(-3\right)-3=0$$

Multiply 9 and -3 to get -27.

$$12x-27a-3=0$$

Add 27a to both sides. Anything plus zero gives itself.

$$12x-3=27a$$

Add 3 to both sides.

$$12x=27a+3$$

Divide both sides by 12.

$$\frac{12x}{12}=\frac{27a+3}{12}$$

Dividing by 12 undoes the multiplication by 12.

$$x=\frac{27a+3}{12}$$

Divide 27a+3 by 12.

$$x=\frac{9a+1}{4}$$

Variable x cannot be equal to any of the values -3,3.

$$x=\frac{9a+1}{4}\text{, }x\neq -3\text{ and }x\neq 3$$

Solve for a

$$a=\frac{4x-1}{9}$$

$$|x|\neq 3$$

Steps for Solving Linear Equation

Multiply both sides of the equation by \left(x-3\right)\left(x+3\right).

$$-4\left(-3\right)x+3a\times 3\left(-3\right)-3=0$$

Multiply -4 and -3 to get 12.

$$12x+3a\times 3\left(-3\right)-3=0$$

Multiply 3 and 3 to get 9.

$$12x+9a\left(-3\right)-3=0$$

Multiply 9 and -3 to get -27.

$$12x-27a-3=0$$

Subtract 12x from both sides. Anything subtracted from zero gives its negation.

$$-27a-3=-12x$$

Add 3 to both sides.

$$-27a=-12x+3$$

The equation is in standard form.

$$-27a=3-12x$$

Divide both sides by -27.

$$\frac{-27a}{-27}=\frac{3-12x}{-27}$$

Dividing by -27 undoes the multiplication by -27.

$$a=\frac{3-12x}{-27}$$

Divide -12x+3 by -27.

$$a=\frac{4x-1}{9}$$

Solve for x

$$x=\frac{9a+1}{4}$$

$$a\neq \frac{11}{9}\text{ and }a\neq -\frac{13}{9}$$

Steps for Solving Linear Equation

Variable x cannot be equal to any of the values -3,3 since division by zero is not defined. Multiply both sides of the equation by \left(x-3\right)\left(x+3\right).

$$-4\left(-3\right)x+3a\times 3\left(-3\right)-3=0$$

Multiply -4 and -3 to get 12.

$$12x+3a\times 3\left(-3\right)-3=0$$

Multiply 3 and 3 to get 9.

$$12x+9a\left(-3\right)-3=0$$

Multiply 9 and -3 to get -27.

$$12x-27a-3=0$$

Add 27a to both sides. Anything plus zero gives itself.

$$12x-3=27a$$

Add 3 to both sides.

$$12x=27a+3$$

Divide both sides by 12.

$$\frac{12x}{12}=\frac{27a+3}{12}$$

Dividing by 12 undoes the multiplication by 12.

$$x=\frac{27a+3}{12}$$

Divide 27a+3 by 12.

$$x=\frac{9a+1}{4}$$

Variable x cannot be equal to any of the values -3,3.

$$x=\frac{9a+1}{4}\text{, }x\neq -3\text{ and }x\neq 3$$