Solve -4^2*(-1/2)^-3/(-frac{1{8})^-2}

$$\frac { - 4 ^ { 2 } \cdot ( - \frac { 1 } { 2 } ) ^ { - 3 } } { ( - \frac { 1 } { 8 } ) ^ { - 2 } }$$

Evaluate

$$2$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$\frac{-16\left(-\frac{1}{2}\right)^{-3}}{\left(-\frac{1}{8}\right)^{-2}}$$

Calculate -\frac{1}{2} to the power of -3 and get -8.

$$\frac{-16\left(-8\right)}{\left(-\frac{1}{8}\right)^{-2}}$$

Multiply -16 and -8 to get 128.

$$\frac{128}{\left(-\frac{1}{8}\right)^{-2}}$$

Calculate -\frac{1}{8} to the power of -2 and get 64.

$$\frac{128}{64}$$

Divide 128 by 64 to get 2.

$$2$$

Factor

$$2$$