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\frac{\left(-4+5i\right)i}{6i^{2}}
Multiply both numerator and denominator by imaginary unit i.
\frac{\left(-4+5i\right)i}{-6}
By definition, i^{2} is -1. Calculate the denominator.
\frac{-4i+5i^{2}}{-6}
Multiply -4+5i times i.
\frac{-4i+5\left(-1\right)}{-6}
By definition, i^{2} is -1.
\frac{-5-4i}{-6}
Do the multiplications in -4i+5\left(-1\right). Reorder the terms.
\frac{5}{6}+\frac{2}{3}i
Divide -5-4i by -6 to get \frac{5}{6}+\frac{2}{3}i.
Re(\frac{\left(-4+5i\right)i}{6i^{2}})
Multiply both numerator and denominator of \frac{-4+5i}{6i} by imaginary unit i.
Re(\frac{\left(-4+5i\right)i}{-6})
By definition, i^{2} is -1. Calculate the denominator.
Re(\frac{-4i+5i^{2}}{-6})
Multiply -4+5i times i.
Re(\frac{-4i+5\left(-1\right)}{-6})
By definition, i^{2} is -1.
Re(\frac{-5-4i}{-6})
Do the multiplications in -4i+5\left(-1\right). Reorder the terms.
Re(\frac{5}{6}+\frac{2}{3}i)
Divide -5-4i by -6 to get \frac{5}{6}+\frac{2}{3}i.
\frac{5}{6}
The real part of \frac{5}{6}+\frac{2}{3}i is \frac{5}{6}.