Solve -3,5+(-1,2)*3/3-(-1,2)

$$\frac { - 3,5 + ( - 1,2 ) \cdot 3 } { 3 - ( - 1,2 ) }$$

Evaluate

$$-\frac{71}{42}\approx -1,69047619$$

Solution Steps

Multiply -1,2 and 3 to get -3,6.

$$\frac{-3,5-3,6}{3-\left(-1,2\right)}$$

Subtract 3,6 from -3,5 to get -7,1.

$$\frac{-7,1}{3-\left(-1,2\right)}$$

The opposite of -1,2 is 1,2.

$$\frac{-7,1}{3+1,2}$$

Add 3 and 1,2 to get 4,2.

$$\frac{-7,1}{4,2}$$

Expand \frac{-7,1}{4,2} by multiplying both numerator and the denominator by 10.

$$\frac{-71}{42}$$

Fraction \frac{-71}{42} can be rewritten as -\frac{71}{42} by extracting the negative sign.

$$-\frac{71}{42}$$

Factor

$$-\frac{71}{42} = -1\frac{29}{42} = -1.6904761904761905$$