Solve -3A^2/A^2+9A+3

$$\frac { - 3 A ^ { 2 } } { A ^ { 2 } + 9 A } + 3$$

Evaluate

$$\frac{27}{A+9}$$

Short Solution Steps

Factor the expressions that are not already factored in \frac{-3A^{2}}{A^{2}+9A}.

$$\frac{-3A^{2}}{A\left(A+9\right)}+3$$

Cancel out A in both numerator and denominator.

$$\frac{-3A}{A+9}+3$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 3 times \frac{A+9}{A+9}.

$$\frac{-3A}{A+9}+\frac{3\left(A+9\right)}{A+9}$$

Since \frac{-3A}{A+9} and \frac{3\left(A+9\right)}{A+9} have the same denominator, add them by adding their numerators.

$$\frac{-3A+3\left(A+9\right)}{A+9}$$

Do the multiplications in -3A+3\left(A+9\right).

$$\frac{-3A+3A+27}{A+9}$$

Combine like terms in -3A+3A+27.

$$\frac{27}{A+9}$$

Factor

$$\frac{27}{A+9}$$