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Real Part
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\frac{\left(-3+2i\right)i}{1i^{2}}
Multiply both numerator and denominator by imaginary unit i.
\frac{\left(-3+2i\right)i}{-1}
By definition, i^{2} is -1. Calculate the denominator.
\frac{-3i+2i^{2}}{-1}
Multiply -3+2i times i.
\frac{-3i+2\left(-1\right)}{-1}
By definition, i^{2} is -1.
\frac{-2-3i}{-1}
Do the multiplications in -3i+2\left(-1\right). Reorder the terms.
2+3i
Divide -2-3i by -1 to get 2+3i.
Re(\frac{\left(-3+2i\right)i}{1i^{2}})
Multiply both numerator and denominator of \frac{-3+2i}{i} by imaginary unit i.
Re(\frac{\left(-3+2i\right)i}{-1})
By definition, i^{2} is -1. Calculate the denominator.
Re(\frac{-3i+2i^{2}}{-1})
Multiply -3+2i times i.
Re(\frac{-3i+2\left(-1\right)}{-1})
By definition, i^{2} is -1.
Re(\frac{-2-3i}{-1})
Do the multiplications in -3i+2\left(-1\right). Reorder the terms.
Re(2+3i)
Divide -2-3i by -1 to get 2+3i.
2
The real part of 2+3i is 2.