Solve -20x-x^2/x+10+-20x-x^2/-x-10

$$\frac { - 20 x - x ^ { 2 } } { x + 10 } + \frac { - 20 x - x ^ { 2 } } { - x - 10 }$$

Evaluate

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Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of x+10 and -x-10 is x+10. Multiply \frac{-20x-x^{2}}{-x-10} times \frac{-1}{-1}.

$$\frac{-20x-x^{2}}{x+10}+\frac{-\left(-20x-x^{2}\right)}{x+10}$$

Since \frac{-20x-x^{2}}{x+10} and \frac{-\left(-20x-x^{2}\right)}{x+10} have the same denominator, add them by adding their numerators.

$$\frac{-20x-x^{2}-\left(-20x-x^{2}\right)}{x+10}$$

Do the multiplications in -20x-x^{2}-\left(-20x-x^{2}\right).

$$\frac{-20x-x^{2}+20x+x^{2}}{x+10}$$

Combine like terms in -20x-x^{2}+20x+x^{2}.

$$\frac{0}{x+10}$$

Zero divided by any non-zero term gives zero.

$$0$$

Factor

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