Solve -2x^0/(-3x)^0+(x^-1)/3x^-2

$$\frac { - 2 x ^ { 0 } } { ( - 3 x ) ^ { 0 } } + \frac { ( x ^ { - 1 } ) } { 3 x ^ { - 2 } }$$

Evaluate

$$\frac{x}{3}-2$$

Short Solution Steps

Calculate x to the power of 0 and get 1.

$$\frac{-2}{\left(-3x\right)^{0}}+\frac{x^{-1}}{3x^{-2}}$$

Calculate -3x to the power of 0 and get 1.

$$\frac{-2}{1}+\frac{x^{-1}}{3x^{-2}}$$

Anything divided by one gives itself.

$$-2+\frac{x^{-1}}{3x^{-2}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent.

$$-2+\frac{x^{1}}{3}$$

Calculate x to the power of 1 and get x.

$$-2+\frac{x}{3}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply -2 times \frac{3}{3}.

$$-\frac{2\times 3}{3}+\frac{x}{3}$$

Since -\frac{2\times 3}{3} and \frac{x}{3} have the same denominator, add them by adding their numerators.

$$\frac{-2\times 3+x}{3}$$

Do the multiplications in -2\times 3+x.

$$\frac{-6+x}{3}$$

Factor

$$\frac{x-6}{3}$$