Solve -2c^2+8/8x=0

$$\frac { - 2 c ^ { 2 } + 8 } { 8 x } = 0$$

Solve for c

$$c=2$$

$$c=-2\text{, }x\neq 0$$

Steps by Finding Square Root

Multiply both sides of the equation by 8x.

$$-2c^{2}+8=0$$

Subtract 8 from both sides. Anything subtracted from zero gives its negation.

$$-2c^{2}=-8$$

Divide both sides by -2.

$$c^{2}=\frac{-8}{-2}$$

Divide -8 by -2 to get 4.

$$c^{2}=4$$

Take the square root of both sides of the equation.

$$c=2 c=-2$$

Steps Using the Quadratic Formula

Multiply both sides of the equation by 8x.

$$-2c^{2}+8=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute -2 for a, 0 for b, and 8 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$c=\frac{0±\sqrt{0^{2}-4\left(-2\right)\times 8}}{2\left(-2\right)}$$

Square 0.

$$c=\frac{0±\sqrt{-4\left(-2\right)\times 8}}{2\left(-2\right)}$$

Multiply -4 times -2.

$$c=\frac{0±\sqrt{8\times 8}}{2\left(-2\right)}$$

Multiply 8 times 8.

$$c=\frac{0±\sqrt{64}}{2\left(-2\right)}$$

Take the square root of 64.

$$c=\frac{0±8}{2\left(-2\right)}$$

Multiply 2 times -2.

$$c=\frac{0±8}{-4}$$

Now solve the equation c=\frac{0±8}{-4} when ± is plus. Divide 8 by -4.

$$c=-2$$

Now solve the equation c=\frac{0±8}{-4} when ± is minus. Divide -8 by -4.

$$c=2$$

The equation is now solved.

$$c=-2 c=2$$

Solve for x (complex solution)

$$x\neq 0$$

$$c=2\text{ or }c=-2$$

Solve for x

$$x\neq 0$$

$$|c|=2$$