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\frac{-2\times 7\sqrt{3}}{\sqrt{3}}+20
Factor 147=7^{2}\times 3. Rewrite the square root of the product \sqrt{7^{2}\times 3} as the product of square roots \sqrt{7^{2}}\sqrt{3}. Take the square root of 7^{2}.
\frac{-14\sqrt{3}}{\sqrt{3}}+20
Multiply -2 and 7 to get -14.
\frac{-14\sqrt{3}\sqrt{3}}{\left(\sqrt{3}\right)^{2}}+20
Rationalize the denominator of \frac{-14\sqrt{3}}{\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
\frac{-14\sqrt{3}\sqrt{3}}{3}+20
The square of \sqrt{3} is 3.
\frac{-14\times 3}{3}+20
Multiply \sqrt{3} and \sqrt{3} to get 3.
\frac{-42}{3}+20
Multiply -14 and 3 to get -42.
-14+20
Divide -42 by 3 to get -14.
6
Add -14 and 20 to get 6.