Solve frac{-2^3+sqrt{6-2}}{|24-(-2)|}

$$\frac { - 2 ^ { 3 } + \sqrt { 6 - 2 } } { | 24 - ( - 2 ) | }$$

Evaluate

$$-\frac{3}{13}\approx -0.230769231$$

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$\frac{-8+\sqrt{6-2}}{|24-\left(-2\right)|}$$

Subtract 2 from 6 to get 4.

$$\frac{-8+\sqrt{4}}{|24-\left(-2\right)|}$$

Calculate the square root of 4 and get 2.

$$\frac{-8+2}{|24-\left(-2\right)|}$$

Add -8 and 2 to get -6.

$$\frac{-6}{|24-\left(-2\right)|}$$

The opposite of -2 is 2.

$$\frac{-6}{|24+2|}$$

Add 24 and 2 to get 26.

$$\frac{-6}{|26|}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of 26 is 26.

$$\frac{-6}{26}$$

Reduce the fraction \frac{-6}{26} to lowest terms by extracting and canceling out 2.

$$-\frac{3}{13}$$

Factor

$$-\frac{3}{13} = -0.23076923076923078$$