Solve -2^2-(-3)^2+5^0/sqrt{16+9}

$$\frac { - 2 ^ { 2 } - ( - 3 ) ^ { 2 } + 5 ^ { 0 } } { \sqrt { 16 + 9 } }$$

Evaluate

$$-\frac{12}{5}=-2.4$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$\frac{-4-\left(-3\right)^{2}+5^{0}}{\sqrt{16+9}}$$

Calculate -3 to the power of 2 and get 9.

$$\frac{-4-9+5^{0}}{\sqrt{16+9}}$$

Subtract 9 from -4 to get -13.

$$\frac{-13+5^{0}}{\sqrt{16+9}}$$

Calculate 5 to the power of 0 and get 1.

$$\frac{-13+1}{\sqrt{16+9}}$$

Add -13 and 1 to get -12.

$$\frac{-12}{\sqrt{16+9}}$$

Add 16 and 9 to get 25.

$$\frac{-12}{\sqrt{25}}$$

Calculate the square root of 25 and get 5.

$$\frac{-12}{5}$$

Fraction \frac{-12}{5} can be rewritten as -\frac{12}{5} by extracting the negative sign.

$$-\frac{12}{5}$$

Factor

$$-\frac{12}{5} = -2\frac{2}{5} = -2.4$$