Solve -1/2b*6/7b^2

$$\frac { - 1 } { 2 b } \cdot \frac { 6 } { 7 b ^ { 2 } }$$

Evaluate

$$-\frac{3}{7b^{3}}$$

Solution Steps

Multiply \frac{-1}{2b} times \frac{6}{7b^{2}} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-6}{2b\times 7b^{2}}$$

Cancel out 2 in both numerator and denominator.

$$\frac{-3}{7bb^{2}}$$

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$\frac{-3}{7b^{3}}$$

Differentiate w.r.t. b

$$\frac{9}{7b^{4}}$$