Solve -1/12-(7/12*2/3/4/3)

$$\frac { - 1 } { 12 } - ( \frac { \frac { 7 } { 12 } \times \frac { 2 } { 3 } } { 4 / 3 } )$$

Evaluate

$$-\frac{3}{8}=-0.375$$

Solution Steps

Fraction \frac{-1}{12} can be rewritten as -\frac{1}{12} by extracting the negative sign.

$$-\frac{1}{12}-\frac{\frac{7}{12}\times \frac{2}{3}}{\frac{4}{3}}$$

Multiply \frac{7}{12} times \frac{2}{3} by multiplying numerator times numerator and denominator times denominator.

$$-\frac{1}{12}-\frac{\frac{7\times 2}{12\times 3}}{\frac{4}{3}}$$

Do the multiplications in the fraction \frac{7\times 2}{12\times 3}.

$$-\frac{1}{12}-\frac{\frac{14}{36}}{\frac{4}{3}}$$

Reduce the fraction \frac{14}{36} to lowest terms by extracting and canceling out 2.

$$-\frac{1}{12}-\frac{\frac{7}{18}}{\frac{4}{3}}$$

Divide \frac{7}{18} by \frac{4}{3} by multiplying \frac{7}{18} by the reciprocal of \frac{4}{3}.

$$-\frac{1}{12}-\frac{7}{18}\times \frac{3}{4}$$

Multiply \frac{7}{18} times \frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$-\frac{1}{12}-\frac{7\times 3}{18\times 4}$$

Do the multiplications in the fraction \frac{7\times 3}{18\times 4}.

$$-\frac{1}{12}-\frac{21}{72}$$

Reduce the fraction \frac{21}{72} to lowest terms by extracting and canceling out 3.

$$-\frac{1}{12}-\frac{7}{24}$$

Least common multiple of 12 and 24 is 24. Convert -\frac{1}{12} and \frac{7}{24} to fractions with denominator 24.

$$-\frac{2}{24}-\frac{7}{24}$$

Since -\frac{2}{24} and \frac{7}{24} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-2-7}{24}$$

Subtract 7 from -2 to get -9.

$$\frac{-9}{24}$$

Reduce the fraction \frac{-9}{24} to lowest terms by extracting and canceling out 3.

$$-\frac{3}{8}$$

Factor

$$-\frac{3}{8} = -0.375$$