Solve -1+3/4-1/3/2-frac{1{4}}=

$$\frac { - 1 + \frac { 3 } { 4 } - \frac { 1 } { 3 } } { 2 - \frac { 1 } { 4 } } =$$

Evaluate

$$-\frac{1}{3}\approx -0.333333333$$

Solution Steps

Convert -1 to fraction -\frac{4}{4}.

$$\frac{-\frac{4}{4}+\frac{3}{4}-\frac{1}{3}}{2-\frac{1}{4}}$$

Since -\frac{4}{4} and \frac{3}{4} have the same denominator, add them by adding their numerators.

$$\frac{\frac{-4+3}{4}-\frac{1}{3}}{2-\frac{1}{4}}$$

Add -4 and 3 to get -1.

$$\frac{-\frac{1}{4}-\frac{1}{3}}{2-\frac{1}{4}}$$

Least common multiple of 4 and 3 is 12. Convert -\frac{1}{4} and \frac{1}{3} to fractions with denominator 12.

$$\frac{-\frac{3}{12}-\frac{4}{12}}{2-\frac{1}{4}}$$

Since -\frac{3}{12} and \frac{4}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{-3-4}{12}}{2-\frac{1}{4}}$$

Subtract 4 from -3 to get -7.

$$\frac{-\frac{7}{12}}{2-\frac{1}{4}}$$

Convert 2 to fraction \frac{8}{4}.

$$\frac{-\frac{7}{12}}{\frac{8}{4}-\frac{1}{4}}$$

Since \frac{8}{4} and \frac{1}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-\frac{7}{12}}{\frac{8-1}{4}}$$

Subtract 1 from 8 to get 7.

$$\frac{-\frac{7}{12}}{\frac{7}{4}}$$

Divide -\frac{7}{12} by \frac{7}{4} by multiplying -\frac{7}{12} by the reciprocal of \frac{7}{4}.

$$-\frac{7}{12}\times \frac{4}{7}$$

Multiply -\frac{7}{12} times \frac{4}{7} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-7\times 4}{12\times 7}$$

Do the multiplications in the fraction \frac{-7\times 4}{12\times 7}.

$$\frac{-28}{84}$$

Reduce the fraction \frac{-28}{84} to lowest terms by extracting and canceling out 28.

$$-\frac{1}{3}$$

Factor

$$-\frac{1}{3} = -0.3333333333333333$$