Solve -0,125*5/(1frac{28{63}-17/21)*77/8}

$$\frac { - 0,125 \cdot 5 } { ( 1 \frac { 28 } { 63 } - \frac { 17 } { 21 } ) \cdot 7 \frac { 7 } { 8 } }$$

Evaluate

$$-0,125$$

Solution Steps

Multiply -0,125 and 5 to get -0,625.

$$\frac{-0,625}{\left(\frac{1\times 63+28}{63}-\frac{17}{21}\right)\times \frac{7\times 8+7}{8}}$$

Multiply 1 and 63 to get 63.

$$\frac{-0,625}{\left(\frac{63+28}{63}-\frac{17}{21}\right)\times \frac{7\times 8+7}{8}}$$

Add 63 and 28 to get 91.

$$\frac{-0,625}{\left(\frac{91}{63}-\frac{17}{21}\right)\times \frac{7\times 8+7}{8}}$$

Reduce the fraction \frac{91}{63} to lowest terms by extracting and canceling out 7.

$$\frac{-0,625}{\left(\frac{13}{9}-\frac{17}{21}\right)\times \frac{7\times 8+7}{8}}$$

Least common multiple of 9 and 21 is 63. Convert \frac{13}{9} and \frac{17}{21} to fractions with denominator 63.

$$\frac{-0,625}{\left(\frac{91}{63}-\frac{51}{63}\right)\times \frac{7\times 8+7}{8}}$$

Since \frac{91}{63} and \frac{51}{63} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-0,625}{\frac{91-51}{63}\times \frac{7\times 8+7}{8}}$$

Subtract 51 from 91 to get 40.

$$\frac{-0,625}{\frac{40}{63}\times \frac{7\times 8+7}{8}}$$

Multiply 7 and 8 to get 56.

$$\frac{-0,625}{\frac{40}{63}\times \frac{56+7}{8}}$$

Add 56 and 7 to get 63.

$$\frac{-0,625}{\frac{40}{63}\times \frac{63}{8}}$$

Multiply \frac{40}{63} times \frac{63}{8} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-0,625}{\frac{40\times 63}{63\times 8}}$$

Cancel out 63 in both numerator and denominator.

$$\frac{-0,625}{\frac{40}{8}}$$

Divide 40 by 8 to get 5.

$$\frac{-0,625}{5}$$

Expand \frac{-0,625}{5} by multiplying both numerator and the denominator by 1000.

$$\frac{-625}{5000}$$

Reduce the fraction \frac{-625}{5000} to lowest terms by extracting and canceling out 625.

$$-\frac{1}{8}$$

Factor

$$-0,125$$