Solve -8/9-1/3/frac{2{3}+1}

$$\frac { - \frac { 8 } { 9 } - \frac { 1 } { 3 } } { \frac { 2 } { 3 } + 1 }$$

Evaluate

$$-\frac{11}{15}\approx -0.733333333$$

Solution Steps

Least common multiple of 9 and 3 is 9. Convert -\frac{8}{9} and \frac{1}{3} to fractions with denominator 9.

$$\frac{-\frac{8}{9}-\frac{3}{9}}{\frac{2}{3}+1}$$

Since -\frac{8}{9} and \frac{3}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{-8-3}{9}}{\frac{2}{3}+1}$$

Subtract 3 from -8 to get -11.

$$\frac{-\frac{11}{9}}{\frac{2}{3}+1}$$

Convert 1 to fraction \frac{3}{3}.

$$\frac{-\frac{11}{9}}{\frac{2}{3}+\frac{3}{3}}$$

Since \frac{2}{3} and \frac{3}{3} have the same denominator, add them by adding their numerators.

$$\frac{-\frac{11}{9}}{\frac{2+3}{3}}$$

Add 2 and 3 to get 5.

$$\frac{-\frac{11}{9}}{\frac{5}{3}}$$

Divide -\frac{11}{9} by \frac{5}{3} by multiplying -\frac{11}{9} by the reciprocal of \frac{5}{3}.

$$-\frac{11}{9}\times \frac{3}{5}$$

Multiply -\frac{11}{9} times \frac{3}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-11\times 3}{9\times 5}$$

Do the multiplications in the fraction \frac{-11\times 3}{9\times 5}.

$$\frac{-33}{45}$$

Reduce the fraction \frac{-33}{45} to lowest terms by extracting and canceling out 3.

$$-\frac{11}{15}$$

Factor

$$-\frac{11}{15} = -0.7333333333333333$$